Chip with simple program for Toy

[Joe]

"CFoley1064" <cfoley1064@aol.com> wrote in message
news:20041012015304.26518.00002157@mb-m03.aol.com...

Subject: getting the right part # from mouser
From: "anonymous" anonymous@catfarm.com
Date: 10/11/2004 11:13 PM Central Daylight Time
Message-id: <oRIad.245546$3l3.214465@attbi_s03

Im trying to find .047uF and 47pF non surface mount caps.. and I can't
seem
to get the site to cough up the correct part #. Any suggestions on how to
phrase my search query?

Also - whats the diff between linear and audio pots? lin vs log I can
understand.


Go to mouser.com, and work from the product guide on the left side of the
main
page. Follow the string from passives to caps to the type you want.

Mouser has so many through-hole caps that, even working down to general
purpose, you've got hundreds of choices. It's not the ideal way to
search.
Sometimes, nothing beats having the catalog, and the Mouser catalog will
be
sent for free if you just get to the request page, available from the main
page. I think having Mouser and Digi-Key catalogs on the desk is a good
idea.

If this is a hobbyist application, you're bogged down with too many
choices,
and you're not particular about specs and need to get this done on the
web, try
Jameco. They're fast and inexpensive.

Audio volume is logarithmic -- an audio pot is a log pot. See:

http://sound.westhost.com/pots.htm

For the graph.

Good luck
Chris

Another way, I just found this out the other day, is when you go to the
mouser site, you will see the'part search' box with the search button next
to it. Enter the value of the part number you are looking for e.g. .047uf
into the box and click search. You will get, for that particular part, 642
matching records which you can then select by mfgr, or category. That's kind
of a long way to do it tho. Having the catalog is easier.

hth,
Joe

 

[Jonathan Kirwan]

On Tue, 12 Oct 2004 16:45:50 -0500, "Steve Nosko"
<suteuve.nosukowicuz@moutouroula.com> wrote:

Alan,

John Popelish got a good start with "e is a natural constant that has
some very sweet properties in many applications of mathematics, and
simplifying..."

Then, it looked as thought John Jardine was going to steal my thunder with
"the voltage knows nothing about how it's "supposed" to behave. "

This could resolve to a mater of faith Alan.

Indeed, the voltage/current "knows" nothing.

After observing what happens in such circuits, "we" (those who must
understand all things) very carefully examined what was going on and
"discovered" that there were mathematical expressions or equations which
would model what happens in nature. "We" came up with theories about what
was going on and what was causing it to happen. "We" then found ways to
make the math fit reality.

Reminds me of Galileo writing in "The Assayer," saying:

"Philosophy is written in this grand book-I mean the universe-which stands
continually open to our gaze, but it cannot be understood unless one first
learns to comprehend the language and interpret the characters in which it is
written. It is written in the language of mathematics, and its characters are
triangles, circles, and other geometric figures, without which it is humanly
impossible to understand a single word of it; without these, one is wandering
about in a dark labyrinth."

(By the way, to anyone who has NOT actually read The Assayer from beginning to
end, I highly recommend it!)

Mathematics is a wonderful world all of its own, independent of nature, yet
where it often turns out that insights in that world happen to happily suggest
relationships found in this world and where proper deductions there imply proper
deductions here. The language is sufficiently rigorous that someone two
millennia before me can describe a circle using it and I can read it today,
knowing absolutely nothing about their lives, their fads or interests, their
politics or style of dress, and come away with exactly the same image in mind
with exactly the same deductive power. In short, mathematics is a quantitative
language that speaks across culture, time, and place. And there is nothing we
have to compare with that.

The processes of science work to achieve a relatively objective process that
works well. It requires the use of objective language sufficient for rigorous
quantitative deductions (by anyone adequately trained in the language) to
specific circumstances, insists that such language both explain past results
well and (more importantly) also make accurate and repeatable predictions,
requires quantitative prediction for discernment, and requires time and patience
for the resulting critical opinion of others skilled in the field to arrive at a
consensus. But mathematics *is* a key part of this objective language used in
science because of its demonstrated congruencies with nature.

In the case of time constants, we have a natural
phenomena which is very nicely described by the equations stated elsewhere
in this thread (the 1/e thingy). It is just like the F=MA equation. "We"
discovered that the force applied to a mass is equal to the mass times the
acceleration. The Mass knows nothing about force, acceleration or
mathematics. We found that this math describes nature.

One thing to keep in mind is that ideas like "density," a useful relationship
between volume and mass, are truly discovered through hard work and through
trying to find some kind of useful discernment regarding sinking and floating.
One doesn't just naturally _know_ about density, as our direct senses tell us
nothing of the kind. It's discovered and then taught and learned. And such
relationships are about parsimonious tools for prediction.

And yes, we have been fortunate that some math describes some nature.

It is exactly like a model airplane (or whatever). We make the model to
look like the real thing. The real thing knows not of the model that we
built, but if we did a good job, I or you can now look at the model and
"know" just how the real thing looks.

It can also be that the model ignores some of the unimportant details of the
"real thing" and still be quite useful. Or that it ignores some important
details, but that so long as we keep those boundaries and limitations in mind
the model is still quite useful for many other things.

I like your example.

The math behind all of our sciences is just like this. *WE* found math
which models reality and because we did such a good job, we can now "do the
math" and "know" how the real thing should behave.

We can also disappear into the mathematical universe and discover brand new
relationships there and have some expectation that where such new territory is
true there, it will probably be found true in the real world as well. One can
make important discoveries using mathematics and use them to suggest what can be
searched out and found here. Surprising, at times.

To be a little more specific, in the case of the time constant. we have
theories about current flow, charge, capacitance, inductance magnetism and
resistance which are borne out by countless experiments and then by
subsequent usage. These theories have all had mathematics fitted to them,
and by golly everything fits. We can now plug-in values to equations till
the cows come home and holy-cripes! The real thing does just what the math
predicted. Based upon the properties we have observed for each type of
component, this math works out such that this 1/e thingy fits just right.

In other words, the answer is: "It just does!"

Yup. In the capacitor case, for example, I idealized it as a simple
differential equation. Real capacitors are more complex, but the ideal is often
close enough in practice to be useful.

Enjoyed seeing your thunder!

Jon

 

[CFoley1064]

Subject: Free iPods? Is it a scam?

Yes.

Chris

 

[Linden]

Hi.
To make an steady output DURING the duration of the 20 Hz AC ring
cadence, you have to replace RD with a full wave rectifier, and its
output filtered.
The size of the filter capacitors will determine the duration of the
steady output by integration. It may even last between rings.
That will be about 200 Volts DC, that must be current limited to drive
an optoisolator to feed the microcontroller at logic levels.
Miguel

Thanks, i've setup your RD circuit without the sidactor and 33V zener.
D1=1N4148, OPTO=4N25 but my /RINGDET just never goes low enough.

i.e Vcc=5v, /ringdet goes from 4.95V down to only 3.5V on each ring so I
think the opto LED doesnt have enough forward voltage across it ??

-Linden.

 

[Spajky]

On 11 Oct 2004 05:20:50 -0700, pascaldamian@icqmail.com (Pascal
Damian) wrote:

The sales rep that sold me AC told me that my AC unit will consume
about 1400W when starting up, then 700W *constantly* regardless of
temperature setting (e.g. 20C vs 25C). Is that true? I'm guessing not,
but I'm not sure.

quite true for a an 2KW thermal power one ...
--
Regards, SPAJKY ÂŽ
& visit my site @ http://www.spajky.vze.com
"Tualatin OC-ed / BX-Slot1 / inaudible setup!"
E-mail AntiSpam: remove ##

 

[Spajky]

On 11 Oct 2004 08:00:36 -0700, john_20_28_2000@yahoo.com (jm) wrote:

It is an older pentium mobo. It is useless. Not even ebay will do
good for me. Should I just throw it away or save it for parts? I
don't know what parts on it I should get. Thanks for opinions.

I use them to "canibalize" them for parts (mostly LowESR caps) for
repairing other damaged MoBo´s ...
--
Regards, SPAJKY ÂŽ
& visit my site @ http://www.spajky.vze.com
"Tualatin OC-ed / BX-Slot1 / inaudible setup!"
E-mail AntiSpam: remove ##

 

[peterken]

Seeing your schematic, I might say forget those textbook examples for
regulators, DON'T use them without an elco at the output since usually it's
a no-go.

I only see .1uF at the output of the regulator.
Regs are rather sensitive to input ripple and output current variations.
Input caps' size looks OK to me.
Try compensating by buffering the output with an elco of say 2200u instead
of larger input cap, so that any possible fed-through ripple gets caught by
the output cap.
By "under buffered" I meant "not having enough of energy reservoir
(capacity) at the output to handle voltage/current variations".

Above I assume your wall wart is capable of delivering enough current, but
as a side assumption :
As far as I seem to read, all 4 individual regs take appprox 400mA, thus
1.6A together
Is your wall wart capable of handling this ?
If not, input voltage will drop until a level where input ripple (lower
level) drops below 12V , thus making it impossible of regulating using a
7809

For your info also this:
It IS possible using a 78xx series regulator and boost it's output current
by using a simple setup as follows
(copy and paste "image" below with a fixed font, say courier, in notepad)

power transistor, pnp
-----------o-\ /---------------
| | v_/ |
| .1u | | |
| === / 33R |
| === \ +--------+ |
| 2R2 | / | | |
--o---/\/\/\-o---o---- 7809 ---o----o--- 9V
| | | | |
=== +----|---+ === ===
=== | === ===
| | | |
--o------------------------o-------o----o---
3500u .1u 2200u

Explanation:
For low currents the transistor is closed, reg takes it all
If reg current increases to say 0.32A, voltage drop over 2R2 will rise
enough to open the transistor (Vbe rises above say 0.7V), thus having the
transistor take everything above 0.32A output current.
Transistor type has to be capable of handling the output current, in your
case I'd say BD138 or something similar.
This setup uses a SINGLE reg and ONE transistor with few discretes instead
of 4 regs and buffering

greetz


"anonymous" <anonymous@catfarm.com> wrote in message
news:w0Xad.235005$D%.43775@attbi_s51...
"under buffered"? can you be more specific?


"peterken" <peter273@hotmail.com> wrote in message
news:YxUad.276795$ih6.14215215@phobos.telenet-ops.be...

simple
as far as I see the output of the regulator is totally under-buffered
try putting an extra elco at the output of the reg, say 2200u something

 

[tempus fugit]

A couple of things are screwy here. First, a daisy chain is when you use one
effect to power the rest. A few of the Boss pedals (like the NS2 noise
suppressor) have 2 DC power jacks - one for the incoming DC, and the other
to connect to the next pedal. You have 4 separate regulators, so pulling one
or any or all of them isn't going to hurt anything.

Another thing you should double check is polarity. Some pedals use a centre
positive connection and others centre negative. If you have things connected
the wrong way, look out! Do you have the positive DC connected to the
positive pin on the plug?

"anonymous" <anonymous@catfarm.com> wrote in message
news:XjIad.245466$3l3.44875@attbi_s03...

"tempus fugit" <toccata@no.spam.ciaccess.com> wrote in message
news:OhGad.591$57.51@fe51.usenetserver.com...
One other question: Why do you have 4 7809s at the output? You could get
away with just one and run parallel lines to each effect from the one
ouptut. I wonder if you've got some goofy ground loop with all these
regulators.
FWIW I power 5 effects and a tuner with one wall wart connected to a
single
7809 with about the same filtering you have here with no problems. Your
plan
should work.
Also, have you tried the obvious culprits (bad cables, connectors, etc)?
Have you tried plugging in one effect at a time to see if any single
effect
is the problem? Have you double checked your solder connections and
wiring?





Weeeell... Ill try removing 3 of them. I didn't want to mess with a daisy
chain.

When I plug in my Boss DS-1 (which should draw 5mA max) I get tons of hum
and not much sound. Plugging in the echo box doesn't work at all. Both
work
fine from the boss wall wart.

This circuit shouldn't be giving me fits like this. I think its a rite of
passage.

 

[tempus fugit]

No. Current is drawn, not pushed. It's kind of like having a well full of
water. You lower a bucket down there and draw what you need. The extra water
in the well is not going to force itself into the bucket until it bursts.

Think of it as having 1.5A available if you need it.


"anonymous" <anonymous@catfarm.com> wrote in message
newsmIad.350483$mD.296451@attbi_s02...

WARNING - dumb question follows - WARNING

consider yourself warned.

So I have a nice transformer that puts out 25V and 1.5A. I want to step it
down to 9V with some voltage regulators. The regulators say they are rated
for 1A and 37V max (given proper heat sinking).

If the output of the regulator is drawing < 100mA - do I have to worry
about
the remaining output from the transformer?

 

[anonymous]

Above I assume your wall wart is capable of delivering enough current, but
as a side assumption :
As far as I seem to read, all 4 individual regs take appprox 400mA, thus
1.6A together
Is your wall wart capable of handling this ?
If not, input voltage will drop until a level where input ripple (lower
level) drops below 12V , thus making it impossible of regulating using a
7809

Each regulator requires 400mA just to function *at all*? I didn't know this.
My wall wart only puts out 400mA. Where would I look up this information?
(more specifically - where did you get it from?)

 

[R. Steve Walz]

anonymous wrote:

WARNING - dumb question follows - WARNING

consider yourself warned.

So I have a nice transformer that puts out 25V and 1.5A. I want to step it
down to 9V with some voltage regulators. The regulators say they are rated
for 1A and 37V max (given proper heat sinking).

If the output of the regulator is drawing < 100mA - do I have to worry about
the remaining output from the transformer?
------------

Nope, nope, nope, the transformer generates a voltage, which then
ONLY pushes the current it is ALLOWED to push by the load resistance.

-Steve
--
-Steve Walz rstevew@armory.com ftp://ftp.armory.com/pub/user/rstevew
Electronics Site!! 1000's of Files and Dirs!! With Schematics Galore!!
http://www.armory.com/~rstevew or http://www.armory.com/~rstevew/Public

 

[Linden]

Linden wrote:

Hi.
To make an steady output DURING the duration of the 20 Hz AC ring
cadence, you have to replace RD with a full wave rectifier, and its
output filtered.
The size of the filter capacitors will determine the duration of the
steady output by integration. It may even last between rings.
That will be about 200 Volts DC, that must be current limited to drive
an optoisolator to feed the microcontroller at logic levels.
Miguel


Thanks, i've setup your RD circuit without the sidactor and 33V zener.
D1=1N4148, OPTO=4N25 but my /RINGDET just never goes low enough.

i.e Vcc=5v, /ringdet goes from 4.95V down to only 3.5V on each ring so I
think the opto LED doesnt have enough forward voltage across it ??

-Linden.

All the ring detect circuits I have seen around the place look similar,
but for the life of me I cannot get a 5 - 0v swing on the ouput of the
optoisolator. Usually only 5 - 3.5V during the ring. When putting a PNP
transistor on the output to give proper logic levels it further reduces
the swing from 5V - 4.5V during the ring and this is not enough to
switch the transistor. Ive tried a couple of opto's now (H11G1 and 4N25)
and get similar results.

It switches properly using DC input instead of the telephone line
though! So obviously the line is not turning on the opto LED enough ??
Frustrating for an amateur !

- Linden.

 

[Alexei Zyuzin]

Or you also could measure the inductance of the inner conductor and
capacitance between the inner conductor and the shield. Z0=sqrt(L/C)

Regards


"Roy McCammon" <rbmccammon@mmm.com> wrote in message
news:416BD3A9.2090004@mmm.com...

Archer wrote:
Roy McCammon <barkupine-news@yahoo.com> wrote in message
news:<415DAD43.1030306@yahoo.com>...

you the impedence (complex) with the far end
shorted and with it open and the characteristic
impedence is the (complex) geometric mean of those
two measurements.

Archer wrote:

how to measure the characteristic impedance of a coax?
I'm starting to study the rf circuit design.


may i measure the impedence using meter?

I suppose you might do with a vector volt meter. Not sure.
Been too long since I used one. I'd use a scope.

and how would it be done that measure the open far end coax?

you don't measure at the far end. you just short the far end
or open the far end.




--
local optimization seldom leads to global optimization

my e-mail address is: <my first name> <my last name> AT mmm DOT com

 

[peterken]

NOPE
I didn't tell you regs need 400mA to function *at all*
(wonder where you read this, jeses)
Regs of this type work with output currents from 0 upto 1A, see datasheets


"anonymous" <anonymous@catfarm.com> wrote in message
news:TN2bd.460950$8_6.164900@attbi_s04...

Above I assume your wall wart is capable of delivering enough current, but
as a side assumption :
As far as I seem to read, all 4 individual regs take appprox 400mA, thus
1.6A together
Is your wall wart capable of handling this ?
If not, input voltage will drop until a level where input ripple (lower
level) drops below 12V , thus making it impossible of regulating using a
7809

Each regulator requires 400mA just to function *at all*? I didn't know this.
My wall wart only puts out 400mA. Where would I look up this information?
(more specifically - where did you get it from?)

 

[colin]

"jm" <john_20_28_2000@yahoo.com> wrote in message
news:c67e4bdd.0410101942.64820fb2@posting.google.com...

I am going to build a device like a remote control finder. I think I
could eventually figure out a circuit that makes a noise, but what
would I look at for the wireless part of it? Should I just take apart
my cordless phone and look!

Thanks, don't know what to look at.

how about a long peice of string ?

Colin =^.^=

 

[anonymous]

"peterken" <peter273@hotmail.com> wrote in message
news:0R4bd.277227$Ti1.14313598@phobos.telenet-ops.be...

NOPE
I didn't tell you regs need 400mA to function *at all*
(wonder where you read this, jeses)
Regs of this type work with output currents from 0 upto 1A, see datasheets


"anonymous" <anonymous@catfarm.com> wrote in message
news:TN2bd.460950$8_6.164900@attbi_s04...

Above I assume your wall wart is capable of delivering enough current,
but
as a side assumption :
As far as I seem to read, all 4 individual regs take appprox 400mA, thus
1.6A together

My bad. Thats how I read your previous posting.

 

[peterken]

Just get one without built-in supply, then you can experiment whatever you
are building *even* on stability with respect to power supply
Also, depending on what you are trying, more as one supply is needed so put
money in a decent dual output supply of say 6...10A 0..30V


"jm" <john_20_28_2000@yahoo.com> wrote in message
news:c67e4bdd.0410081606.7e4d3293@posting.google.com...
Should I buy a breadboard with a 5 volt regulated power supply or get
a regular breadboard without one?

Thank you.

 

[Steve Evans]

On Mon, 11 Oct 2004 23:54:00 GMT, "Joe Rocci" <joe@roccis.com> wrote:

Steve,

If the inductor was not there to hold the zero-crossings of the input sine
wave at zero volts, then the whole waveform would sink toward a lower DC
voltage because it is capacitively coupled. You can prove this to yourself
by taking a large capacitor and driving a diode that is connected to ground.
The test can easily be done with audio frequencies if you don't have RF
equipment. You could also simulate it on a program like SPICE.

If the choke were removed from the circuit, this input DC shift would
reverse bias the BE junction, preventing the abiltiy of the waveform to
drive current into the BE junction. No base current = no collector current =
no gain.

BTW, I was almost sure your original post said this was a multiplier
circuit. Did the word "multiplier" not appear in it anywhere? Hmmm...

Thanks for the explanation, Joe, but no. I never said anythink about
multiplicaiton.

steve
--

Fat, sugar, salt, beer: the four essentials for a healthy diet.

 

[Joe Rocci]

Thanks for the explanation, Joe, but no. I never said anythink about
multiplicaiton

Steve,
Can you send me a copy of the original post? When these things happen, I
like to see where my crazy notions came from.

Joe
W3JDR

 

[Rich Grise]

On Wed, 13 Oct 2004 10:26:07 -0700, Gill wrote:

Hi, I'm hoping someone out there can help me. I have a seventh grade son
who must do a Science Fair project. He has chosen to do a project based on
"Alternative Energy". His goal is to power his GameBoy using some form of
power other than batteries or electricity. Any and all alternative energy
sources are being considered.

Design a VR suit that's coupled with cranks and levers and pushrods and
stuff to a generator, so the game is powered by the player's own movements.

;-)

Good Luck!
Rich