Record for boombox?

[Walter E.]

I have a small boombox with CD, tape and radio. It has speakers, but no
output jack to a headphone or to connect it to my computer input.

I opened it up. If I run parallel leads to the speakers, put a resistor in
line and put an audio jack at the end of the leads, will that work as a
headphone outlet and input to the computer? Or, is there more to it?

If so, any idea what the resistor should be? Probably high impedance like
100K ?

Thanks for helping an old tinkerer.

--
Walter
The Happy Iconoclast www.rationality.net
-

 

[Gary Tait]

On Sat, 19 Jul 2003 23:24:13 GMT, "Walter E." <wer25@yahoo.com> wrote:

I have a small boombox with CD, tape and radio. It has speakers, but no
output jack to a headphone or to connect it to my computer input.

I opened it up. If I run parallel leads to the speakers, put a resistor in
line and put an audio jack at the end of the leads, will that work as a
headphone outlet and input to the computer? Or, is there more to it?

If so, any idea what the resistor should be? Probably high impedance like
100K ?

Thanks for helping an old tinkerer.

For headphone, you need a dual switch headphone jack (has two isolated
switch contacts, in addition to the headphone contacts. Wire it so
thate the NC contact on the switch braks the speaker wire, and either
connect the headhone contact to the amp out, or the NO contact, with a
150 Ohm 1/2 watt resistor. The amp out would go to the Comon contact.
You would do that twice, once for each channel. Or get a straight
headphone jack, ad a separate SPDT or DPT switch to break the
speakers.

For the line out, just connect an RCA jack to the outside terminals of
the volume control, or the common terminal of the source selector
switch.

 

[Richard Crowley]

"Walter E." wrote ...

Why should I put a resistor in each of the positive
leads from the speaker to the headphones? Why
not put one resistor in the common lead to the
ground?

Because that will tend to "mix" left & right together
(to an extent determined by the impedance of the
phones and your common current-limiting resistor.)