R
Robert Monsen
Guest
I just built the one you referenced (http://members.shaw.ca/roma/ under
Circuits, #23,) and it works properly with a 2N2222A.
Note that the transistor is 'backwards', ie, the emitter is connected to the
1.5k from V+. Also, I had to crank up my power supply to about 8.5v before
it would start oscillating. Lower than that, it didn't oscillate.
I put the base and emitter on my scope, and it looks like the transistor is
acting like a zener, holding off the current until the voltage gets to about
8.2 volts. At that point, the base starts getting more positive. When the
base gets to .6V, the voltage shoots up briefly, and the emitter voltage
drop to 0.
My guess as to whats happening is that the emitter-base junction is leaking
charge at 8.2V, which is charging up the base. When the base-collector
junction gets forward biased (base up to .6V,) current flows, causing an
avalanche breakdown of some kind in the emitter-base junction. This quickly
discharges the capacitor, so the current drops enough to stop the breakdown
and restart the charging cycle. Its like a UJT oscillator.
Regards
"Watson A.Name - 'Watt Sun'" <alondra101@hotmail.com> wrote in message
news:MPG.198e065ffb9f073989b27@news.inreach.net...
Circuits, #23,) and it works properly with a 2N2222A.
Note that the transistor is 'backwards', ie, the emitter is connected to the
1.5k from V+. Also, I had to crank up my power supply to about 8.5v before
it would start oscillating. Lower than that, it didn't oscillate.
I put the base and emitter on my scope, and it looks like the transistor is
acting like a zener, holding off the current until the voltage gets to about
8.2 volts. At that point, the base starts getting more positive. When the
base gets to .6V, the voltage shoots up briefly, and the emitter voltage
drop to 0.
My guess as to whats happening is that the emitter-base junction is leaking
charge at 8.2V, which is charging up the base. When the base-collector
junction gets forward biased (base up to .6V,) current flows, causing an
avalanche breakdown of some kind in the emitter-base junction. This quickly
discharges the capacitor, so the current drops enough to stop the breakdown
and restart the charging cycle. Its like a UJT oscillator.
Regards
"Watson A.Name - 'Watt Sun'" <alondra101@hotmail.com> wrote in message
news:MPG.198e065ffb9f073989b27@news.inreach.net...
In article <a7076635.0307271049.10a532c5@posting.google.com>,
bigcat@meeow.co.uk mentioned...
testing_h@yahoo.com (Andre) wrote:
Hi group
Anyone got below 4 parts + LED (rules :- no chips with more than 4
pins, no PUTs or UJT's, no inductors, no hand picled parts ) ?
So far I have got down to 6 parts + LED, using a regulator IC .
Hi
another one: resistor + capacitor + neon to make a neon flasher.
Supply V should be close to neon Vbreakdown. Now put LED in series
with the R so LED lights during C charging, but goes out as C nears
Vmax.
Of course you dont need the LED, you could in most cases leave that
out.
Which brings to mind the flasher that is shown on some electronics
websites. It is a LED and a C-B junction of a transistor, connected
so that it is reverse biased, and also a capacitor. It's here
http://members.shaw.ca/roma/ under Circuits, #23. The ones I've built
don't work. This is similar to a neon light flasher.
Regards, NT
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