S
Steven O.
Guest
Okay, this is a homework problem, but I'm middle-aged and already have
my B.A., and just returning to school to pick up a little more
knowledge. Besides, you can clearly see (below) that I'm giving this
my best shot. So, someone please help me out here. For a basic
electronics class, we are given that the temperature coefficient for
the resistance of a material is given by:
a (for alpha) = (1/R)(dR/dT), and we are asked to show that:
R2 = {[ 1 + a(T1 - Ts) ] / [1 + a(T2 - Ts)]} R2
where Ts is the "reference temperature".
But here is how the math works out for me:
a = (1/R)(dR/dT)
dR/R = a dT Take indefinite integral of both sides....
ln R = a T + Ts, where Ts is said reference temperature
Assume R1 corresponds to T1, and R2 to T2, then....
ln R1 = a T1 + Ts, and ln R2 = a T2 + Ts
ln R1 - ln R2 = a (T1 - T2), so Ts is already gone.
ln (R1/R2) = a (T1 - T2), exponentiate both sides...
R1/R2 = exp (a [T1 - T2])
exp x is approximately 1 + x, so we have,
R1 = R2 { (1 + a [T1 - T2]) }, which is not the professor's desired
result. Did the professor screw up, or have I forgotten some basic
calculus or algebra in twenty years since college? Thanks in advance
for all replies....
Steve O.
"Spying On The College Of Your Choice" -- How to pick the college that is the Best Match for a high school student's needs.
www.SpyingOnTheCollegeOfYourChoice.com
my B.A., and just returning to school to pick up a little more
knowledge. Besides, you can clearly see (below) that I'm giving this
my best shot. So, someone please help me out here. For a basic
electronics class, we are given that the temperature coefficient for
the resistance of a material is given by:
a (for alpha) = (1/R)(dR/dT), and we are asked to show that:
R2 = {[ 1 + a(T1 - Ts) ] / [1 + a(T2 - Ts)]} R2
where Ts is the "reference temperature".
But here is how the math works out for me:
a = (1/R)(dR/dT)
dR/R = a dT Take indefinite integral of both sides....
ln R = a T + Ts, where Ts is said reference temperature
Assume R1 corresponds to T1, and R2 to T2, then....
ln R1 = a T1 + Ts, and ln R2 = a T2 + Ts
ln R1 - ln R2 = a (T1 - T2), so Ts is already gone.
ln (R1/R2) = a (T1 - T2), exponentiate both sides...
R1/R2 = exp (a [T1 - T2])
exp x is approximately 1 + x, so we have,
R1 = R2 { (1 + a [T1 - T2]) }, which is not the professor's desired
result. Did the professor screw up, or have I forgotten some basic
calculus or algebra in twenty years since college? Thanks in advance
for all replies....
Steve O.
"Spying On The College Of Your Choice" -- How to pick the college that is the Best Match for a high school student's needs.
www.SpyingOnTheCollegeOfYourChoice.com