Problem with an SGS-Thomson L6203

T

Tony MS

Guest
I guess this question is addressed to anyone who has used one of these
successfully.

The device is an H-bridge driver with separate inputs for each
channel.

I've wired it up as per the datasheet, supply voltage 12V, and with
Enable wired high at 5V. When either IN1 or IN2 is high, OUT1 or OUT2
is correctly at 12V and delivers full power. But, when either is low,
the corresponding OUT is disabled, ie sits at 0V, but with high
internal impedance, and no ability to deliver power.

I've wired up a second circuit, in case the problem was that I'd
damaged the chip, but same problem

Anyone got any ideas?
 
Tony MS wrote...
I've wired it up as per the datasheet, supply voltage 12V, and with
Enable wired high at 5V. When either IN1 or IN2 is high, OUT1 or OUT2
is correctly at 12V and delivers full power. But, when either is low,
the corresponding OUT is disabled, ie sits at 0V, but with high
internal impedance, and no ability to deliver power.
At 0V it shouldn't be able to "deliver power," but you're saying
that it's high-Z (can be pulled high) and refuses to sink current?
What did you do with the "sense" connection, did you ground it?
Or ground it through a low-value current-sensing resistor?

Thanks,
- Win

whill_at_picovolt-dot-com (use hill_at_rowland-dot-org for now)
 
Thanks. Grounding sense solved the problem

Cheers

Tony

"Winfield Hill" <Winfield_member@newsguy.com> wrote in message
news:c679m002j0p@drn.newsguy.com...
Tony MS wrote...
I've wired it up as per the datasheet, supply voltage 12V, and with
Enable wired high at 5V. When either IN1 or IN2 is high, OUT1 or OUT2
is correctly at 12V and delivers full power. But, when either is low,
the corresponding OUT is disabled, ie sits at 0V, but with high
internal impedance, and no ability to deliver power.
At 0V it shouldn't be able to "deliver power," but you're saying
that it's high-Z (can be pulled high) and refuses to sink current?
What did you do with the "sense" connection, did you ground it?
Or ground it through a low-value current-sensing resistor?

Thanks,
- Win

whill_at_picovolt-dot-com (use hill_at_rowland-dot-org for now)
 

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