daily puzzle...

R

RichD

Guest
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich
 
On 09/14/20 23:30, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A<--> E, B<--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich

45 degrees...

Chris
 
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.

CH
 
On Monday, September 14, 2020 at 4:23:15 PM UTC-7, Clifford Heath wrote:
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.

Yep, but if you don\'t see that, the dot product of the simple vectors gives the same answer.
 
On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,


--
Jasen.
 
This idiotic troll is repeating the answer already given...

--
Jasen Betts <jasen@xnet.co.nz> wrote:

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From: Jasen Betts <jasen@xnet.co.nz
Newsgroups: sci.electronics.design
Subject: Re: daily puzzle
Organization: JJ\'s own news server
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Xref: reader02.eternal-september.org sci.electronics.design:608096

On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,


--
Jasen.
 

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