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daily puzzle...

R

RichD

Guest
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich
 
C

Chris

Guest
On 09/14/20 23:30, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A<--> E, B<--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich
45 degrees...

Chris
 
C

Clifford Heath

Guest
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -
60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.

CH
 
W

whit3rd

Guest
On Monday, September 14, 2020 at 4:23:15 PM UTC-7, Clifford Heath wrote:
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.
Yep, but if you don\'t see that, the dot product of the simple vectors gives the same answer.
 
J

Jasen Betts

Guest
On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?
60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,


--
Jasen.
 
J

John Doe

Guest
This idiotic troll is repeating the answer already given...

--
Jasen Betts <jasen@xnet.co.nz> wrote:

Path: eternal-september.org!reader02.eternal-september.org!feeder.eternal-september.org!aioe.org!peer03.ams4!peer.am4.highwinds-media.com!peer01.iad!feed-me.highwinds-media.com!news.highwinds-media.com!fx35.iad.POSTED!not-for-mail
From: Jasen Betts <jasen@xnet.co.nz
Newsgroups: sci.electronics.design
Subject: Re: daily puzzle
Organization: JJ\'s own news server
Message-ID: <rjp9ju$5uv$1@gonzo.revmaps.no-ip.org
References: <616bccb2-a20c-4c74-94d4-eb33d467daa6n@googlegroups.com
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Xref: reader02.eternal-september.org sci.electronics.design:608096

On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,


--
Jasen.
 
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