# daily puzzle...

R

#### RichD

##### Guest
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich

C

#### Chris

##### Guest
On 09/14/20 23:30, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A<--> E, B<--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -

--
Rich
45 degrees...

Chris

C

#### Clifford Heath

##### Guest
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

You have two minutes, no calculator, pen and paper only -
60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.

CH

W

#### whit3rd

##### Guest
On Monday, September 14, 2020 at 4:23:15 PM UTC-7, Clifford Heath wrote:
On 15/9/20 8:30 am, RichD wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees.

BD, BG and DG are all diagonals of a square, so it\'s an equilateral
triangle.
Yep, but if you don\'t see that, the dot product of the simple vectors gives the same answer.

J

#### Jasen Betts

##### Guest
On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?
60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,

--
Jasen.

J

#### John Doe

##### Guest

--
Jasen Betts <jasen@xnet.co.nz> wrote:

From: Jasen Betts <jasen@xnet.co.nz
Newsgroups: sci.electronics.design
Subject: Re: daily puzzle
Organization: JJ\'s own news server
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Date: Tue, 15 Sep 2020 02:41:02 -0000 (UTC)

On 2020-09-14, RichD <r_delaney2001@yahoo.com> wrote:
A quickie. No diagram, but no need.

Given a unit cube, vertices labeled ABCD on the top face,
EFGH on the bottom; where A <--> E, B <--> F, etc.
Draw diagonals GD and BD, across the appropriate faces.

What is the angle GDB?

60 degrees it\'s an equilateral triangle.

GDBE is a regular tetrahedron,

--
Jasen.