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elektroda.net NewsGroups Forum Index - Repair Electronics - **Engine run time to keep battery charged**

Guest

Mon Feb 04, 2019 11:45 pm

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

--

Guest

Tue Feb 05, 2019 12:45 am

Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

5 min once every two weeks should be sufficient assuming the

battery and charging system is good. Turn everything off except

engine. It will need to be run at least 1,000 rpm for that time

period.

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

Guest

Tue Feb 05, 2019 2:45 am

On Monday, February 4, 2019 at 5:57:03 PM UTC-5, Paul in Houston TX wrote:

Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

5 min once every two weeks should be sufficient assuming the

battery and charging system is good. Turn everything off except

engine. It will need to be run at least 1,000 rpm for that time

period.

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

5 min once every two weeks should be sufficient assuming the

battery and charging system is good. Turn everything off except

engine. It will need to be run at least 1,000 rpm for that time

period.

I've always been told that short run times creates condensation and acid in the motor oil from incomplete warmup - get her good and hot to drive off moisture. I realize the OP was asking about charging times, but he'd be better served by letting that old Buick idle for a good half an hour every few weeks, or better yet, have OP take the old girl for a blast.

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

NOOOOOOOOOOO!!!!!! Don't suggest a solution (even a cheap one) that comes from a credit card lest Arlen Holder or one of his socks pitches a fit!!!

Guest

Tue Feb 05, 2019 2:45 am

On Mon, 4 Feb 2019 16:45:34 -0500, Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

72 seconds

Having said that, here's how I arrived at 72 seconds, bearing in mind

there's a complexity to your question which, outside of the engineering

specs of both the battery & engine (and parasitics), we can only help you

guess at it mathematically, where empirical results would seem to be more

accurate than our guestimates.

Starting with the basics, a quick search for a Buick Regal Alternator nets

<https://www.partsgeek.com/catalog/1987/buick/regal/engine_electrical/alternator.html>

which says the alternator outputs 100 amps at idle (if needed) and 150 amps

output at max rpm (again, if needed as alternators adjust output based on

"B" sensing).

Running a direct search for the power needed to start an 87 Buick Regal,

it's easy to find the vehicle, but hard to find the power needed to start

the engine:

<https://en.wikipedia.org/wiki/Buick_Regal#Grand_National,_Turbo-T,_T-Type,_and_GNX>

We're kind of stuck with the "generic" stuff, such as this:

o How Many Amps Does It Take to Start a Car?

<https://www.reference.com/vehicles/many-amps-start-car-e35b6f3d4d8bf426>

Which says an average car needs 400 to 500 amps but doesn't say how long.

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum power would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

If I did the math right, that's less than 1.5 amp hours, and since we

guessed high, I'd say the amount used is roughly about 1 amp hour to 1.5

amp hours, but since we want to "be safe" and have "easy math", I'd use 2

amp hours as the amount to add back.

If you put back two amp hours (to cover for inherent losses, mostly in

heat), you're back to where you started, where we have to "assume" that the

battery sense circuit allows the alternator to output enough current to

charge the battery after just one start.

At idle, if we assume the battery sense allows you to get those 100 amps we

saw in the spec, to generate 2 amp hours would take only about 0.02 hours,

or about 72 seconds (if I did the quick math right) - which -

coincidentally - is about how long it took to run the quick math. :)

If that 72 second answer is wrong, I welcome someone who can tell us how to

arrive at the better answer.

Guest

Tue Feb 05, 2019 2:45 am

On Tue, 5 Feb 2019 01:30:54 -0000 (UTC), arlen holder wrote:

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum _power _would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

the maximum _power _would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

Ooops... Coulombs ... not power... (power would be via P=IV or I^2R but

not amp seconds)...

(I hacked that out in a minute on the run, so, please correct where I err.)

Guest

Tue Feb 05, 2019 2:45 am

On Mon, 4 Feb 2019 17:05:13 -0800 (PST), John-Del wrote:

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

NOOOOOOOOOOO!!!!!! Don't suggest a solution (even a cheap one)

that comes from a credit card lest Arlen Holder or one of his socks

pitches a fit!!!

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

NOOOOOOOOOOO!!!!!! Don't suggest a solution (even a cheap one)

that comes from a credit card lest Arlen Holder or one of his socks

pitches a fit!!!

First off, neither of you appeared to have _comprehended_ the question,

which was how much time does it take to recharge the battery to compensate

for the charge lost in starting, which I roughly calculated at about 72

seconds, meaning, a couple of minutes "should" recharge the battery if the

assumptions I made were reasonable.

Even if you did _comprehend_ the question, you made no attempt to _answer_

the OP's question, which, is par for the course since all you _can_ do is

off-topic chit-chat drivel.

NOTE: I don't need to prove that statement since you prove it for me.

Moving on though, assuming the OP is satisfied with the 72 second

assumption, there _is_ a question of how often he _needs_ to charge the

battery.

I wonder if you, John-Del, have the brains to answer _that_ question?

(HINT: I don't think you do ... but maybe you'll prove me wrong.)

HINT: I already calculated it in the same minute (or so) that I calculated

the answer I provided - but I didn't post it because, unlike you, I

actually _comprehended_ the question that the OP had asked.

HINT: If you can't take a hint - you always prove to be _stupid_, John-Doe.

DOUBLEHINT: The proof will be in exactly what you write in response.

Guest

Tue Feb 05, 2019 4:45 am

On 2/4/19 7:43 PM, arlen holder wrote:

Nothing of interest as usual.

Quack quack quack, ding, reverse direction.

--

"I am a river to my people."

Jeff-1.0

WA6FWi

http:foxsmercantile.com

Guest

Tue Feb 05, 2019 5:45 am

On Mon, 4 Feb 2019 20:59:38 -0600, Fox's Mercantile wrote:

> Quack quack quack, ding, reverse direction.

Two points which _adults_ will comprehend.

1. Snit here acts like a child _all_ the time, and,

2. Snit here didn't even _attempt_ to answer the OP's question.

We really shouldn't fault him as his brain _is_ that of a child.

o He proves that fact in _every_ post - as he did here.

Meanwhile, I at least attempted to faithfully answer the guy's question.

o And, yet, Snit (aka Fox's Mercantile), calls everyone but himself, a troll.

I don't even have to prove these two statements since he proves it himself.

o What Snit (aka Fox's Mercantile) wries, proves these two facts.

1. Snit (aka Fox's Mercantile) is _never_ purposefully helpful, and,

2. Snit (aka Fox's Mercantile) _always_ proves to own the brain of a child.

The funny thing is that it's not even an ad hominem attack!

o It's simply pointing out what Fox's Mercantile proves himself to be a fact.

Guest

Tue Feb 05, 2019 6:45 am

In article <072fc2e7-dc4d-48ac-b069-4fe7224adbac_at_googlegroups.com>,

ohger1s_at_gmail.com says...

I've always been told that short run times creates condensation and acid in the motor oil from incomplete warmup - get her good and hot to drive off moisture. I realize the OP was asking about charging times, but he'd be better served by letting that old Buick idle for a good half an hour every few weeks, or better yet, have OP

take the old girl for a blast.

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

I am using one of those HF float chargers to hold up a lawn mower

battery over the winter. I really use that battery to power a sprayer

instead of the lawn mower.

My mower is in a shed with out power. I have a small solar cell about

the size of a mouse pad to keep it charged over the winter months.

If starting the mower, I would run it long enough to get the motor and

exhaust system hot. Maybe a 5 ot 10 mile trip to the store and back

once every 2 weeks or so. It will probably do the other parts of the

car some good also.

Guest

Tue Feb 05, 2019 6:45 am

On 02/04/2019 08:30 PM, arlen holder wrote:

On Mon, 4 Feb 2019 16:45:34 -0500, Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

72 seconds

Having said that, here's how I arrived at 72 seconds, bearing in mind

there's a complexity to your question which, outside of the engineering

specs of both the battery & engine (and parasitics), we can only help you

guess at it mathematically, where empirical results would seem to be more

accurate than our guestimates.

Starting with the basics, a quick search for a Buick Regal Alternator nets

https://www.partsgeek.com/catalog/1987/buick/regal/engine_electrical/alternator.html

which says the alternator outputs 100 amps at idle (if needed) and 150 amps

output at max rpm (again, if needed as alternators adjust output based on

"B" sensing).

Running a direct search for the power needed to start an 87 Buick Regal,

it's easy to find the vehicle, but hard to find the power needed to start

the engine:

https://en.wikipedia.org/wiki/Buick_Regal#Grand_National,_Turbo-T,_T-Type,_and_GNX

We're kind of stuck with the "generic" stuff, such as this:

o How Many Amps Does It Take to Start a Car?

https://www.reference.com/vehicles/many-amps-start-car-e35b6f3d4d8bf426

Which says an average car needs 400 to 500 amps but doesn't say how long.

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum power would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

If I did the math right, that's less than 1.5 amp hours, and since we

guessed high, I'd say the amount used is roughly about 1 amp hour to 1.5

amp hours, but since we want to "be safe" and have "easy math", I'd use 2

amp hours as the amount to add back.

If you put back two amp hours (to cover for inherent losses, mostly in

heat), you're back to where you started, where we have to "assume" that the

battery sense circuit allows the alternator to output enough current to

charge the battery after just one start.

At idle, if we assume the battery sense allows you to get those 100 amps we

saw in the spec, to generate 2 amp hours would take only about 0.02 hours,

or about 72 seconds (if I did the quick math right) - which -

coincidentally - is about how long it took to run the quick math. :)

If that 72 second answer is wrong, I welcome someone who can tell us how to

arrive at the better answer.

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

72 seconds

Having said that, here's how I arrived at 72 seconds, bearing in mind

there's a complexity to your question which, outside of the engineering

specs of both the battery & engine (and parasitics), we can only help you

guess at it mathematically, where empirical results would seem to be more

accurate than our guestimates.

Starting with the basics, a quick search for a Buick Regal Alternator nets

https://www.partsgeek.com/catalog/1987/buick/regal/engine_electrical/alternator.html

which says the alternator outputs 100 amps at idle (if needed) and 150 amps

output at max rpm (again, if needed as alternators adjust output based on

"B" sensing).

Running a direct search for the power needed to start an 87 Buick Regal,

it's easy to find the vehicle, but hard to find the power needed to start

the engine:

https://en.wikipedia.org/wiki/Buick_Regal#Grand_National,_Turbo-T,_T-Type,_and_GNX

We're kind of stuck with the "generic" stuff, such as this:

o How Many Amps Does It Take to Start a Car?

https://www.reference.com/vehicles/many-amps-start-car-e35b6f3d4d8bf426

Which says an average car needs 400 to 500 amps but doesn't say how long.

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum power would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

If I did the math right, that's less than 1.5 amp hours, and since we

guessed high, I'd say the amount used is roughly about 1 amp hour to 1.5

amp hours, but since we want to "be safe" and have "easy math", I'd use 2

amp hours as the amount to add back.

If you put back two amp hours (to cover for inherent losses, mostly in

heat), you're back to where you started, where we have to "assume" that the

battery sense circuit allows the alternator to output enough current to

charge the battery after just one start.

At idle, if we assume the battery sense allows you to get those 100 amps we

saw in the spec, to generate 2 amp hours would take only about 0.02 hours,

or about 72 seconds (if I did the quick math right) - which -

coincidentally - is about how long it took to run the quick math. :)

If that 72 second answer is wrong, I welcome someone who can tell us how to

arrive at the better answer.

<https://www.jstor.org/stable/44611429?seq=1#page_scan_tab_contents>

It's behind a pay-wall but I can probably get my hands on a copy

Guest

Tue Feb 05, 2019 7:45 am

On Tuesday, 5 February 2019 01:30:57 UTC, arlen holder wrote:

On Mon, 4 Feb 2019 16:45:34 -0500, Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

72 seconds

Having said that, here's how I arrived at 72 seconds, bearing in mind

there's a complexity to your question which, outside of the engineering

specs of both the battery & engine (and parasitics), we can only help you

guess at it mathematically, where empirical results would seem to be more

accurate than our guestimates.

Starting with the basics, a quick search for a Buick Regal Alternator nets

https://www.partsgeek.com/catalog/1987/buick/regal/engine_electrical/alternator.html

which says the alternator outputs 100 amps at idle (if needed) and 150 amps

output at max rpm (again, if needed as alternators adjust output based on

"B" sensing).

Running a direct search for the power needed to start an 87 Buick Regal,

it's easy to find the vehicle, but hard to find the power needed to start

the engine:

https://en.wikipedia.org/wiki/Buick_Regal#Grand_National,_Turbo-T,_T-Type,_and_GNX

We're kind of stuck with the "generic" stuff, such as this:

o How Many Amps Does It Take to Start a Car?

https://www.reference.com/vehicles/many-amps-start-car-e35b6f3d4d8bf426

Which says an average car needs 400 to 500 amps but doesn't say how long.

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum power would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

If I did the math right, that's less than 1.5 amp hours, and since we

guessed high, I'd say the amount used is roughly about 1 amp hour to 1.5

amp hours, but since we want to "be safe" and have "easy math", I'd use 2

amp hours as the amount to add back.

If you put back two amp hours (to cover for inherent losses, mostly in

heat), you're back to where you started, where we have to "assume" that the

battery sense circuit allows the alternator to output enough current to

charge the battery after just one start.

At idle, if we assume the battery sense allows you to get those 100 amps we

saw in the spec, to generate 2 amp hours would take only about 0.02 hours,

or about 72 seconds (if I did the quick math right) - which -

coincidentally - is about how long it took to run the quick math. :)

If that 72 second answer is wrong, I welcome someone who can tell us how to

arrive at the better answer.

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

72 seconds

Having said that, here's how I arrived at 72 seconds, bearing in mind

there's a complexity to your question which, outside of the engineering

specs of both the battery & engine (and parasitics), we can only help you

guess at it mathematically, where empirical results would seem to be more

accurate than our guestimates.

Starting with the basics, a quick search for a Buick Regal Alternator nets

https://www.partsgeek.com/catalog/1987/buick/regal/engine_electrical/alternator.html

which says the alternator outputs 100 amps at idle (if needed) and 150 amps

output at max rpm (again, if needed as alternators adjust output based on

"B" sensing).

Running a direct search for the power needed to start an 87 Buick Regal,

it's easy to find the vehicle, but hard to find the power needed to start

the engine:

https://en.wikipedia.org/wiki/Buick_Regal#Grand_National,_Turbo-T,_T-Type,_and_GNX

We're kind of stuck with the "generic" stuff, such as this:

o How Many Amps Does It Take to Start a Car?

https://www.reference.com/vehicles/many-amps-start-car-e35b6f3d4d8bf426

Which says an average car needs 400 to 500 amps but doesn't say how long.

Let's assume it takes five to ten seconds to start it, at 500 amps, where

the maximum power would be 10 seconds times 500 amps, which means you

sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.

If I did the math right, that's less than 1.5 amp hours, and since we

guessed high, I'd say the amount used is roughly about 1 amp hour to 1.5

amp hours, but since we want to "be safe" and have "easy math", I'd use 2

amp hours as the amount to add back.

If you put back two amp hours (to cover for inherent losses, mostly in

heat), you're back to where you started, where we have to "assume" that the

battery sense circuit allows the alternator to output enough current to

charge the battery after just one start.

At idle, if we assume the battery sense allows you to get those 100 amps we

saw in the spec, to generate 2 amp hours would take only about 0.02 hours,

or about 72 seconds (if I did the quick math right) - which -

coincidentally - is about how long it took to run the quick math. :)

If that 72 second answer is wrong, I welcome someone who can tell us how to

arrive at the better answer.

Best answer so far.

100A would only be delivered to a flat battery, it'll charge much slower than that.

There's also the parasitic loads to make up for, the electronics that eats power when the vehicle is off and on.

You're better off testing battery voltage and not doing anything until it drops enough to warrant charging. Leads acids don't like sitting even half discharged, keep it near full.

NT

Guest

Tue Feb 05, 2019 9:45 am

"Tom Del Rosso" <fizzbintuesday_at_that-google-mail-domain.com> wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

--

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

--

A real test at idle, turn on lights. If revving the engine makes them

brighter, you have little reserve power to charge battery. For a fast

charge you need 14 or more volts.

Greg

Guest

Tue Feb 05, 2019 9:45 am

Ralph Mowery <rmowery28146_at_earthlink.net> wrote:

In article <072fc2e7-dc4d-48ac-b069-4fe7224adbac_at_googlegroups.com>,

ohger1s_at_gmail.com says...

I've always been told that short run times creates condensation and acid

in the motor oil from incomplete warmup - get her good and hot to drive

off moisture. I realize the OP was asking about charging times, but

he'd be better served by letting that old Buick idle for a good half an

hour every few weeks, or better yet, have OP

take the old girl for a blast.

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

I am using one of those HF float chargers to hold up a lawn mower

battery over the winter. I really use that battery to power a sprayer

instead of the lawn mower.

My mower is in a shed with out power. I have a small solar cell about

the size of a mouse pad to keep it charged over the winter months.

If starting the mower, I would run it long enough to get the motor and

exhaust system hot. Maybe a 5 ot 10 mile trip to the store and back

once every 2 weeks or so. It will probably do the other parts of the

car some good also.

ohger1s_at_gmail.com says...

I've always been told that short run times creates condensation and acid

in the motor oil from incomplete warmup - get her good and hot to drive

off moisture. I realize the OP was asking about charging times, but

he'd be better served by letting that old Buick idle for a good half an

hour every few weeks, or better yet, have OP

take the old girl for a blast.

OTH, Harbor Freight has cheap little float chargers but 120v power

will be needed. A friend uses one of these when out of the country:

https://www.harborfreight.com/automatic-battery-float-charger-42292.html

I am using one of those HF float chargers to hold up a lawn mower

battery over the winter. I really use that battery to power a sprayer

instead of the lawn mower.

My mower is in a shed with out power. I have a small solar cell about

the size of a mouse pad to keep it charged over the winter months.

If starting the mower, I would run it long enough to get the motor and

exhaust system hot. Maybe a 5 ot 10 mile trip to the store and back

once every 2 weeks or so. It will probably do the other parts of the

car some good also.

My HF floaters make too much bubbling on a charged battery.

Greg

Guest

Tue Feb 05, 2019 1:45 pm

On Monday, February 4, 2019 at 8:43:17 PM UTC-5, arlen holder wrote:

a bit steaming pile of bullshit

You don't have a clue how to answer that question.

You've left out the variables that *must* be included to calculate the recharge time.

Car batteries have an internal resistance that changes from the minute it's installed until it's finally dead. As it ages, the car battery's internal resistance rises and it won't draw the same current as it did when it was new. Batteries slowly sulfate over time and the more sulfated the car battery is, the larger the battery's capacitor effect is and the longer it takes to charge. Car alternators often don't provide their rated current, particularly when they are older. You left out the temperature of the components and the quality of wiring involved. Is that old Buick even idling at it's programmed rpm?

You also left out the self discharging of the battery and the standby parasitic drag from the car's computer and accessories, so that must be added to the charge time. OP asked about replenishment charge time but he also said he wants to start the car to keep the battery from self discharging. His question was two-fold, and in the real world, the best advice is keep a float charger on it or, better yet, run the car on the road to charge the battery, boil off condensation and contaminants in the fluids, and keep moving parts moving.

If OP starts that car, runs it 72 seconds and shuts it off, that battery won't last.

Guest

Tue Feb 05, 2019 1:45 pm

On Monday, February 4, 2019 at 4:45:38 PM UTC-5, Tom Del Rosso wrote:

If you turn over an engine periodically to keep it charged, how long do

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

--

you run it to make up for the charge lost in starting?

In this case it's my neighbor's 87 Buick Regal while he's in the

hospital.

--

God Help Us! This was given in Drivers'Ed. I must be VERY old.

The rules of thumb are as follows. All times at ~1,000 rpm.

a) For a pre-catalyst car, a minimum of 15 minutes. This will bring every part of the system above the temperatures necessary to boil water out of the oil and the exhaust. This will also re-coat the cylinders with oil - which tends to be rinsed off by the very rich mixture on starting, especially when the outside temperatures are below freezing.

b) Post-Catalyst, carburetor: About the same, maybe only 10 - 12 minutes, as the catalyst will do a fine job of heating the exhaust. A V8 or other large-displacement engine will take longer.

c) Fuel-injected, 7 - 12 minutes. This directly related to engine displacement. Big = more time.

The physics of removing moisture from the oil becomes the driver (pun intended). The system must reach full operating temperature and stay there for a couple of minutes. Pretty much when moisture (steam) stops coming out of the tailpipe - and then a few minutes.

If you open the oil-fill cap and find a milky foam, you haven't been doing it long enough.

elektroda.net NewsGroups Forum Index - Repair Electronics - **Engine run time to keep battery charged**