Lorraine
Guest
Mon May 23, 2005 9:49 am
Suppose you have a 10 meter long wire, does the current alternative
(rise or fall) at the same time in the entire stretch of the 10 meter
long wire, or does a portion rise up while a portion fall down?
Lor
Lorraine
Guest
Mon May 23, 2005 12:31 pm
I see.
Anyway. In Alternating Current. Isn't it the voltage is the one
alternating from 110 volts to -110 volts. How come it's not
called Alternating Voltage?
Suppose the voltage is going down from 110 volts to 0. What
happens to the value of the current? How about the one where
it goes down from 0 to -110. What happens to the value of
the current in between the transition.
Tnx
Lorr
Lorraine
Guest
Mon May 23, 2005 2:31 pm
Vidar Løkken wrote:
Quote:
Lorraine wrote:
I see.
Anyway. In Alternating Current. Isn't it the voltage is the one
alternating from 110 volts to -110 volts. How come it's not
called Alternating Voltage?
Because, in a purely resistive load, the current will follow the
voltage
exactly.
However, in a inductive or capacitive load, the current won't follow
the
voltage, but both will alternate. In a inductive load, the current
will
be 90° before the voltage, in a capacitive load, 90° after the
voltage.
Suppose the voltage is going down from 110 volts to 0. What
happens to the value of the current? How about the one where
it goes down from 0 to -110. What happens to the value of
the current in between the transition.
The current decrease (again, in a purely resitive load) as voltage
decrease. Current increase as voltage increase. Remember that 0V and
-110V still has a potential of 110V, you only redefine 0V. You could
as
well swap the terminals and say 110V and 0V. 0V is a question of how
you
define it;) Negative voltage means the current flows opposite
direction
of a positive voltage... The potential is still the same.
--
MVH,
Vidar
www.bitsex.net
Thanks. Last.
Suppose in a DC (Direct Current) circuit with 10 volts source
and 1 ampere. Is there a difference in the current in the wires
if you use a resistor of 10 ohm vs a 10 ohm load (such as a
light bulb)? Does the value of the resistor stand for the amount
of current the load needs?? Does this mean heavier load such
as dc motors has lesser resistance and more current?
Lorr
Lorraine
Guest
Mon May 23, 2005 10:50 pm
Guys,
Suppose you short the wire in the battery. The current will be maximum
right? Suppose it takes 24 hours for the battery to be used up in a
10 ohm load. If you short it, would the battery be used up in say
1 hour. Is the operation of the battery in the shorting mode the same
as in normal only accelerated?
How about AC lines. If you short the wires, it sparks and explodes. So
I assume current is maximum. However, if you use wires that can never
melt or break. What would happen to the other end in the power utility.
Would it destroy their circuit?
Suppose I use a regulated dc supply and I short the + and - outputs.
Would the circuit be damaged or would the wires just heat up without
any
damage to the source? I'm asking this because I plan to use a DC
regulated power supply and make the signal vibrate at 1 Mhz and
direct it to the antennae to experiment with em radiation. I don't
plan to use any resistor because I want the current to be maximum
so the em produced would be maximum. I wonder if this would damage
the source. What sort of protection (diode?) that can be used in the
source to detect and prevent shorting damage (in case this happens).
Thx
Lorr
